Part+One-Determining+the+Variation

The first thing that needs to be done is to determine where to cut the paper on the back wall so that the dimensions of your photograph are directly propotional to the graph paper on the the back of the room. So here goes....

1. Put your name and the version number of your picture on a 3x5 card. 2. Answer the following 3 questions on the index card and hand it in on **Tuesday 11/13/07.**
 * __Directions__**:

The height of the graph paper hanging on the back wall of the classroom varies directly to the height of the picture that you received in class. (Be mindful not everyone has the same size picture of the Taj Mahal.) The height of the graph paper on the back wall that we use for the mural is 29 inches.
 * 1) What is the constant of variation for your picture that you received in class? (Round this answer to the nearest hundredth)
 * 2) What is the equation of variation that relates the dimensions of your picture to the dimensions of the mural on the back wall of the classroom?
 * 3) How wide should we make mural on the back wall of the classrooom so that it is proportional to the picture? (Round this answer to the nearest tenth)

I will be hugely impressed with anyone who posts links here or gives brief descriptions on how to do direct variation. I will be greatly saddened by anyone who posts the answers to the questions here. Remember part of knowing this stuff thoroughly is knowing how to guide and teach other people on how to do it. 1194549282

This site (which I found by typing in "Direct Variation" on Google) expresses how to figure out [|direct variation] and what it is in simple terms. Here is how we will be using direct variation for this project...First, you will have to measure the height of your picture (not the piece of paper, the picture) and this would be considered 'x.' Since the height of the classroom picture (which is indicated in the directions) varies directly with the versions we have, that would be considered 'y.' (Remember, y varies directly with x.) So your formula should contain a missing 'k', because that is what we're solving for...the constant of variation. Divide y by x to find k then plug the answer for k back into the original formula (y=kx) to get the equation of variation. For step 3, you have to use that equation you just found, plug in the width of your picture for x, and multiply them for y. 1194801149

The Results Are In
1. The consant of variation is 4.14 and was computed by doing 29=k(7). 2. The equation of variation is **m=4.14p.** 3. We need to make the width of the mural 44.51. This was computed by doing m=(4.14)(10.75). 1196376606
 * Version One**

1. The consant of variation is 4.29 and was computed by doing 29=k(6.75). 2. The equation of variation is **m=4.29p.** 3. We need to make the width of the mural 43.97. This was computed by doing m=4.29(10.25). 1196632498 1. The consant of variation is 4.46 and was computed by doing 29=k(6.5). 2. The equation of variations is **m=4.46p.** 3. We need to make the width of the mural 44.46. This was computed by doing m=4.46(9.88). 1196638724
 * Version Two**
 * Version Three**

1. The consant of variation is 4.64 and was computed by doing 29=k(9.5). 2. The equation of variation is **m=4.64p.** 3. We need to make the width of the mural 44. This was computed by doing m=4.64(9.5). 1196646574
 * Version Four**

1. The consant of variation is 4.83 and was computed by doing 29=k(6). 2. The equation of variation is **m=4.83****p.** 3. We need to make the width of the mural 44.1. This was computed by doing m=4.83(9.125). 1196649877
 * Version Five**

1. The consant of variation is 5.04 and was computed by doing 29=k(5.75). 2. The equation of variation is **m=5.04p.** 3. We need to make the width of the mural 44.1. This was computed by doing y=5.04(8.75). 1196822555
 * Version Six**

1. The consant of variation is 5.27 and was computed by doing 29=k(5.5). 2. The equation of variation is **m=5.27p**. 3. We need to make the width of the mural 44.1. This was computed by doing m=5.27(8_3/8) 1196822555~
 * Version Seven**

1. The consant of variation is 5.52 and was computed by doing 29=k(5.25). 2. The equation of variation is **m=5.52p.** 3. We need to make the width of the mural 44.16. This was computed by doing m=5.52(8).1196377267
 * Version Eight**